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7a^2+9a-24=0
a = 7; b = 9; c = -24;
Δ = b2-4ac
Δ = 92-4·7·(-24)
Δ = 753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{753}}{2*7}=\frac{-9-\sqrt{753}}{14} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{753}}{2*7}=\frac{-9+\sqrt{753}}{14} $
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